JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Chord of contact of tangent, Pole and Polar

  • question_answer
    Middle point of the chord of the circle \[{{x}^{2}}+{{y}^{2}}=25\] intercepted on the line \[x-2y=2\]is

    A)            \[\left( \frac{3}{5},\frac{4}{5} \right)\]                                     

    B)            \[(-2,-2)\]

    C)            \[\left( \frac{2}{5},-\frac{4}{5} \right)\]                                    

    D)            \[\left( \frac{8}{3},\frac{1}{3} \right)\]

    Correct Answer: C

    Solution :

               Here the intersection point of chord and circle can be found by solving the equation of circle with the equation of given line, therefore, the points of intersection are (?4, ?3) and\[\left( \frac{24}{5},\ \frac{7}{5} \right)\]. Hence the midpoint is\[\left( \frac{-4+\frac{24}{5}}{2},\ \frac{-3+\frac{7}{5}}{2} \right)=\left( \frac{2}{5},\ -\frac{4}{5} \right)\].


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