JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Chord of contact of tangent, Pole and Polar

  • question_answer
     The distance between the chords of contact of the tangents to the circle \[{{x}^{2}}+{{y}^{2}}+2gx+2fy+c=0\]from the origin and the point \[(g,f)\]is

    A)            \[\frac{1}{2}\left( \frac{{{g}^{2}}+{{f}^{2}}-c}{\sqrt{{{g}^{2}}+{{f}^{2}}}} \right)\]     

    B)             \[\left( \frac{{{g}^{2}}+{{f}^{2}}-c}{\sqrt{{{g}^{2}}+{{f}^{2}}}} \right)\]

    C)            \[\frac{1}{2}\left( \frac{{{g}^{2}}+{{f}^{2}}-c}{{{g}^{2}}+{{f}^{2}}} \right)\]

    D)            None of these

    Correct Answer: A

    Solution :

               Chord of contact from origin \[\equiv gx+fy+c=0\]                    and from \[(g,\ f)\equiv gx+fy+g(x+g)+f(y+f)+c=0\]                    or \[2gx+2fy+{{g}^{2}}+{{f}^{2}}+c=0\]                    \[\therefore \] Distance\[=\frac{\frac{{{g}^{2}}+{{f}^{2}}+c}{2}-c}{\sqrt{{{g}^{2}}+{{f}^{2}}}}\]\[=\frac{{{g}^{2}}+{{f}^{2}}-c}{2\sqrt{{{g}^{2}}+{{f}^{2}}}}\].


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