JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Chord of contact of tangent, Pole and Polar

  • question_answer
    The length of common chord of the circles \[{{(x-a)}^{2}}+{{y}^{2}}={{a}^{2}}\]and \[{{x}^{2}}+{{(y-b)}^{2}}={{b}^{2}}\]is                    [MP PET 1989]

    A)            \[2\sqrt{{{a}^{2}}+{{b}^{2}}}\]                                       

    B)            \[\frac{ab}{\sqrt{{{a}^{2}}+{{b}^{2}}}}\]

    C)            \[\frac{2ab}{\sqrt{{{a}^{2}}+{{b}^{2}}}}\]                    

    D)            None of these

    Correct Answer: B

    Solution :

               Equation of common chord is\[ax-by=0\].                    Now length of common chord                    \[=2\sqrt{r_{1}^{2}-p_{1}^{2}}=2\sqrt{r_{2}^{2}-p_{2}^{2}}\]                    where \[{{r}_{1}}\] and \[{{r}_{2}}\] are radii of given circles and \[{{p}_{1}},\ {{p}_{2}}\] are the perpendicular distances from centres of circles to common chords.                    Hence required length \[=2\sqrt{{{a}^{2}}-\frac{{{a}^{4}}}{{{a}^{2}}+{{b}^{2}}}}=\frac{2ab}{\sqrt{{{a}^{2}}+{{b}^{2}}}}\].


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