A) One mole of \[{{H}_{2}}\]
B) 1/2 mole of \[{{H}_{2}}\]
C) 2/3 mole of \[{{O}_{2}}\]
D) Both 1/2 mol of \[{{H}_{2}}\] and 1/2 mol of \[{{O}_{2}}\]
Correct Answer: B
Solution :
\[M{{g}^{+2}}\equiv {{H}_{2}}\] \[n=\frac{12gm}{24gm}=\frac{1}{2}\]mole of \[{{H}_{2}}\]
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