A) 272 g
B) 403 g
C) 528 g
D) 1056 g
Correct Answer: C
Solution :
\[\underset{132}{\mathop{{{(N{{H}_{4}})}_{2}}S{{O}_{4}}}}\,\equiv 2N{{H}_{3}}\equiv \underset{2(36.5)=73\,gm}{\mathop{2HCl}}\,\] \[73\,g\,HCl\equiv 132\,g{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\] \[292\,g\,HCl=528\,g{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\]You need to login to perform this action.
You will be redirected in
3 sec