A) (i) 25 c.c. (ii) 50 c.c.
B) (i) 50 c.c. (ii) 75 c.c.
C) (i) 25 c.c. (ii) 75 c.c.
D) (i) 75 c.c. (ii) 75 c.c.
Correct Answer: C
Solution :
At room temperature \[2{{H}_{2(g)}}\ \ \ +\ \ \ \ {{O}_{2(g)}}\ \ \to \ \ 2{{H}_{2}}{{O}_{(l)}}\] t =0 50ml 50ml 0 t =t 50 ? 2x 50 ? x 2x =0 25gases (50)liquid In this case \[{{H}_{2}}\]is limiting reagent x = 25ml At 110°C \[2{{H}_{2(g)}}+{{O}_{2(g)}}\to 2{{H}_{2}}{{O}_{(g)}}\] \[{{V}_{\text{gas}}}=75\,ml\] t =t 0 25ml 50ml
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