A) 20 ml of 0.5 M \[{{H}_{2}}{{C}_{2}}{{O}_{4}}\]
B) 50 ml of 0.1 M \[{{H}_{2}}{{C}_{2}}{{O}_{4}}\]
C) 50 ml of 0.5 M \[{{H}_{2}}{{C}_{2}}{{O}_{4}}\]
D) 20 ml of 0.1 M \[{{H}_{2}}{{C}_{2}}{{O}_{4}}\]
Correct Answer: B
Solution :
\[KMn{{O}_{4}}\] Oxalic acid \[\frac{{{M}_{1}}{{V}_{1}}}{{{n}_{1}}}=\]\[\frac{{{M}_{2}}{{V}_{2}}}{{{n}_{2}}}\]; \[\frac{20\times 0.1}{2}=\frac{{{M}_{2}}{{V}_{2}}}{5}\]; \[{{M}_{2}}{{V}_{2}}=5\].
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