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JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry / रसायन की कुछ मूलभूत अवधारणाएँ Question Bank Chemical stoichiometry

  • question_answer
    How much of NaOH is required to neutralise 1500 \[c{{m}^{3}}\]of 0.1 \[N\,HCl\] (Na = 23)                                              [KCET 2001]

    A)                 40 g       

    B)                 4 g

    C)                 6 g          

    D)                 60 g

    Correct Answer: C

    Solution :

               \[N=\frac{\text{W(}gm)\times 1000}{V\times \text{Eq}\text{.wt}\text{.}}\]                    1500ml of 0.1N HCl = 150ml (N)                                 \[1=\frac{\text{W}(gm)\times 1000}{150\times 40}\], W (gm)\[=\frac{150\times 40}{1000}=6gm\].


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