A) 1.2 gm
B) 1.6 gm
C) 2.4 gm
D) 1.8 gm
Correct Answer: C
Solution :
\[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{Z}_{1}}}{{{Z}_{2}}}\] Þ \[{{m}_{2}}=\frac{{{m}_{1}}{{Z}_{2}}}{{{Z}_{1}}}=\frac{14\times 1.2\times {{10}^{-6}}}{7\times {{10}^{-6}}}\]= 2.4 g
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