A) \[0.5\times {{10}^{20}}\]
B) \[1.5\times {{10}^{20}}\]
C) \[3\times {{10}^{20}}\]
D) \[6\times {{10}^{20}}\]
Correct Answer: D
Solution :
Charge supplied per minute = 3.2 ´ 60 = 192 C Charge 2e liberates one Cu+2 ion \No of Cu+2 ion liberate by 192 C \[=\frac{192}{2e}=\frac{192}{2\times 1.6\times {{10}^{-19}}}=6\times {{10}^{20}}\]
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