A) 22.4 A
B) \[19.3\,\,A\]
C) 9.65 A
D) 1 A
Correct Answer: B
Solution :
22.4 litre H2 = 1 mole H2 = N molecules of H2 = 2N atom of H So charge required to liberate 22.4 litre of H2 = 2Ne = 2F Hence charge required to liberate 0.224 litre of H2 \[=\frac{2F}{22.4}\times 0.224\]\[=\frac{2F}{100}=2\times 965\,C\] So current \[i=\frac{Q}{t}=\frac{2\times 965}{100}=19.3\,amp\]
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