A) In the ratio of the densities of Cu and Ag
B) In the ratio of the at weights of Cu and Ag
C) In the ratio of half the atomic weight of Cu to the atomic weight of Ag
D) In the ratio of half the atomic weight of Cu to half the atomic weight of Ag
Correct Answer: C
Solution :
As \[\frac{{{m}_{Cu}}}{{{m}_{Ag}}}=\frac{{{E}_{Cu}}}{{{E}_{Ag}}}=\frac{\frac{1}{2}\,{{(\text{Atomic weight)}}_{Cu}}}{{{(\text{Atomic weight)}}_{Ag}}}\]
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