A) 1 gm
B) 1.5 gm
C) 2 gm
D) 2.5 gm
Correct Answer: B
Solution :
\[m=Zi\,t\] Þ \[m=\frac{ZVt}{R}\]Þ \[m\propto Vt\] Þ \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{V}_{1}}{{t}_{1}}}{{{V}_{2}}{{t}_{2}}}\] Þ \[\frac{2}{{{m}_{2}}}=\frac{12\times 30}{6\times 45}\] Þ \[{{m}_{2}}=1.5\,gm\]
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