A) 0.242 g
B) 0.190 g
C) 0.141 g
D) 0.126 g
Correct Answer: D
Solution :
\[m=Zi\,t\] Þ \[\frac{{{m}_{Cu}}}{{{m}_{Zn}}}=\frac{{{Z}_{Cu}}}{{{Z}_{Zn}}}\] \[{{m}_{Cu}}={{m}_{Zn}}\frac{{{Z}_{Cu}}}{{{Z}_{Zn}}}=0.13\times \frac{31.5}{32.5}=0.126\,g\]
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