A) 0.6 gm
B) 0.09 gm
C) 5.4 gm
D) 10.8 gm
Correct Answer: C
Solution :
\[m=Zi\,t\] or \[m\propto i\,t\] \ \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{i}_{1}}{{t}_{1}}}{{{i}_{2}}{{t}_{2}}}\] Þ\[\frac{9}{{{m}_{2}}}=\frac{{{10}^{5}}}{50\times 20\times 60}\] Þ\[{{m}_{2}}=5.4\,gm\]
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