A) 0.23 gm
B) 1.15 gm
C) 2.3 gm
D) 11.5 gm
Correct Answer: C
Solution :
Amount of metallic sodium appears \[m=Zi\,t=\left( \frac{A}{VF} \right)\,i\,t\] \[=\left( \frac{23}{1\times 96500} \right)\times 16\times 10\times 60\] =2.3 gm
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