A) 4 m
B) \[m/2\]
C) \[m/4\]
D) 2 m
Correct Answer: B
Solution :
By Faraday's law, \[m\propto i\,t.\] \ \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{i}_{1}}{{t}_{1}}}{{{i}_{2}}{{t}_{2}}}\] Þ \[\frac{m}{{{m}_{2}}}=\frac{4\times 120}{6\times 40}\] Þ \[{{m}_{2}}=\frac{m}{2}\]
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