A) 6.4 gm
B) 12.8 gm
C) 3.2 gm
D) 10.8 gm
Correct Answer: C
Solution :
Equivalent weight of copper \[=\frac{64}{2}=32\] \[\frac{\text{Equivalent weight of }Cu}{\text{Equivalent weight of }Ag}=\frac{\text{Weight of }Cu\text{ deposited}}{\text{Weight of }A\text{g deposited}}\] Weight of copper deposited \[=\frac{10.8\times 32}{108}=3.2gm\]
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