A) Atomic weight
B) Molecular weight
C) Chemical equivalent
D) A constant
Correct Answer: C
Solution :
\[\because \] \[\frac{{{Z}_{1}}}{{{Z}_{2}}}=\frac{{{E}_{1}}}{{{E}_{2}}}\] Þ \[{{Z}_{2}}=\left( \frac{{{E}_{2}}}{{{E}_{1}}} \right)\,.\,{{Z}_{1}}\]
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