JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer An organic compound containing C, H and N gave following analysis : C = 40%, H = 13.33% and N = 46.67%. Its empirical formula would be [CBSE PMT 1998, 99; AFMC 2000; KCET 2002; Pb. PMT 2004]

    A) \[{{C}_{2}}{{H}_{7}}{{N}_{2}}\]

    B) \[C{{H}_{5}}N\]

    C) \[C{{H}_{4}}N\]

    D) \[{{C}_{2}}{{H}_{7}}N\]

    Correct Answer: C

    Solution :

      Element        No. of moles     Simple ratio C = 40%             40/12            3.33    1 H = 13.33%       13.33/1         13.33   4 N = 46.67%       46.67/14         3.33  1 Thus formula \[C{{H}_{4}}N\].


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