• # question_answer An organic compound containing C, H and N gave following analysis : C = 40%, H = 13.33% and N = 46.67%. Its empirical formula would be [CBSE PMT 1998, 99; AFMC 2000; KCET 2002; Pb. PMT 2004] A) ${{C}_{2}}{{H}_{7}}{{N}_{2}}$ B) $C{{H}_{5}}N$ C) $C{{H}_{4}}N$ D) ${{C}_{2}}{{H}_{7}}N$

Element        No. of moles     Simple ratio C = 40%             40/12            3.33    1 H = 13.33%       13.33/1         13.33   4 N = 46.67%       46.67/14         3.33  1 Thus formula $C{{H}_{4}}N$.