JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer 64 gm of an organic compound contains 24 gm of carbon, 8 gm of hydrogen and the rest oxygen. The empirical formula of the compound is [MP PMT 1996]

    A) \[C{{H}_{2}}O\]

    B) \[{{C}_{2}}{{H}_{4}}O\]

    C) \[C{{H}_{4}}O\]

    D) \[{{C}_{2}}{{H}_{8}}{{O}_{2}}\]

    Correct Answer: C

    Solution :

    Elements               No. of moles            Simple ratio
    C (24 gm) 24/12 = 2 1
    H (8 gm) 8/1 = 8 4
    O (32 gm) 32/16 = 2 1
    Empirical formula = \[C{{H}_{4}}O\]


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