• # question_answer A hydrocarbon has C=85.72% and remaining H. The hydrocarbon is [MP PET 1996] A) ${{C}_{2}}{{H}_{4}}$ B) ${{C}_{2}}{{H}_{6}}$ C) ${{C}_{2}}{{H}_{2}}$ D) $C{{H}_{4}}$

Empirical formula = ${{C}_{2}}{{H}_{4}}$.