JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer A hydrocarbon has C=85.72% and remaining H. The hydrocarbon is [MP PET 1996]

    A) \[{{C}_{2}}{{H}_{4}}\]

    B) \[{{C}_{2}}{{H}_{6}}\]

    C) \[{{C}_{2}}{{H}_{2}}\]

    D) \[C{{H}_{4}}\]

    Correct Answer: A

    Solution :

    Element                  No. of moles         Simple ratio
    C 85.72% 85.72/12 7.14 = 1
    H 14.18% 14.18/1 14.18 = 2
    Empirical formula = \[{{C}_{2}}{{H}_{4}}\].

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