• # question_answer A compound gave 80% carbon and 20 % hydrogen on analysis. The compound is possibly [MADT Bihar 1984; MP PMT 1986] A) ${{C}_{6}}{{H}_{6}}$ B) ${{C}_{2}}{{H}_{5}}OH$ C) ${{C}_{2}}{{H}_{6}}$ D) $CHC{{l}_{3}}$

Hence formula = $C{{H}_{3}}$ or ${{C}_{2}}{{H}_{6}}$.