JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer An organic compound on analysis gave the following results : C = 54.5%, O = 36.4%, H = 9.1%. The Empirical formula of the compound is [CPMT 1977; KCET 1998; MP PET 2003; UPSEAT 2004;  IIT-JEE (Screening) 2004]

    A) \[C{{H}_{3}}O\]

    B) \[{{C}_{2}}{{H}_{4}}O\]

    C) \[{{C}_{3}}{{H}_{4}}O\]

    D) \[{{C}_{4}}{{H}_{8}}O\]

    Correct Answer: B

    Solution :

    Element                 No. of Moles         Simple Ratio
    C = 54.5 54.5/12 = 4.54 2
    H = 9.1 9.1/1 = 9.1 4
    O = 36.4 36.4/16 = 2.27 1
    Hence, \[{{C}_{2}}{{H}_{4}}O\].


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