• # question_answer An organic compound on analysis gave the following results : C = 54.5%, O = 36.4%, H = 9.1%. The Empirical formula of the compound is [CPMT 1977; KCET 1998; MP PET 2003; UPSEAT 2004;  IIT-JEE (Screening) 2004] A) $C{{H}_{3}}O$ B) ${{C}_{2}}{{H}_{4}}O$ C) ${{C}_{3}}{{H}_{4}}O$ D) ${{C}_{4}}{{H}_{8}}O$

Hence, ${{C}_{2}}{{H}_{4}}O$.