JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer An organic compound contains \[C=38.8%,\] \[H=16%\] and \[N=45.2%\]. Empirical formula of the compound is [CPMT 1973, 83]

    A) \[C{{H}_{3}}N{{H}_{2}}\]

    B) \[C{{H}_{3}}CN\]

    C) \[{{C}_{2}}{{H}_{5}}CN\]

    D) \[C{{H}_{2}}{{(NH)}_{2}}\]

    Correct Answer: A

    Solution :

    Element                 No. of Moles        Simple Ratio
    C = 38.8 38.8/12 = 3.2 1
    H = 16 16/1 = 16 5
    N = 45.2 45.2/14 = 3.2 1
    Therefore, Empirical formula = \[C{{H}_{5}}N\] or \[C{{H}_{3}}N{{H}_{2}}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner