JEE Main & Advanced Chemistry Organic Chemistry: Some Basic Principles & Techniques Question Bank Chemical analysis of organic compounds

  • question_answer Empirical formula of a compound is \[{{C}_{2}}{{H}_{5}}O\] and its molecular weight is 90. Molecular formula of the compound is [NCERT 1971]

    A) \[{{C}_{2}}{{H}_{5}}O\]

    B) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]

    C) \[{{C}_{4}}{{H}_{10}}{{O}_{2}}\]

    D) \[{{C}_{5}}{{H}_{14}}O\]

    Correct Answer: C

    Solution :

    Empirical formula mass =\[{{C}_{2}}{{H}_{5}}O\] = 24+ 5 +16= 45. \[n=\frac{\text{Mol}\text{. mass}}{\text{Emp}\text{. mass}}=\frac{90}{45}=2\] Mol. formula = \[{{({{C}_{2}}{{H}_{5}}O)}_{2}}={{C}_{4}}{{H}_{10}}{{O}_{2}}\].


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