A) \[\text{2}.\text{36}\times \text{1}{{0}^{\text{39}}}\]
B) \[\text{2}.\text{36}\times \text{1}{{0}^{40}}\]
C) \[\text{2}.\text{34}\times \text{1}{{0}^{41}}\]
D) \[\text{2}.\text{34}\times \text{1}{{0}^{42}}\]
Correct Answer: A
Solution :
Gravitational force \[{{F}_{G}}=\frac{G{{m}_{e}}{{m}_{p}}}{{{r}^{2}}}\] \[{{F}_{G}}=\frac{6.7\times {{10}^{-11}}\times 9.1\times {{10}^{-31}}\times 1.6\times {{10}^{-27}}}{{{(5\times {{10}^{-11}})}^{2}}}\]= 3.9 ´ 10?47 N Electrostatic force \[{{F}_{e}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{e}^{2}}}{{{r}^{2}}}\] \[{{F}_{e}}=\frac{9\times {{10}^{9}}\times 1.6\times {{10}^{-19}}\times 1.6\times {{10}^{-19}}}{{{(5\times {{10}^{-11}})}^{2}}}\] = 9.22 ´ 10?8 N So, \[\frac{{{F}_{e}}}{{{F}_{G}}}=\frac{9.22\times {{10}^{-8}}}{3.9\times {{10}^{-47}}}=2.36\times {{10}^{39}}\]You need to login to perform this action.
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