A) \[7.20\,N\]
B) \[11.25\,N\]
C) \[22.50\,N\]
D) \[45.00\,N\]
Correct Answer: B
Solution :
\[F\propto \frac{1}{{{r}^{2}}}\Rightarrow \frac{{{F}_{1}}}{{{F}_{2}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{2}}\]Þ\[\frac{5}{{{F}_{2}}}={{\left( \frac{0.04}{0.06} \right)}^{2}}={{F}_{2}}=11.25\,N\]
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