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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Charge and Coulombs Law

  • question_answer
    When air is replaced by a dielectric medium of constant \[k\], the maximum force of attraction between two charges separated by a distance                                       [CBSE PMT 1999]

    A)                    Decreases \[k\] times      

    B)                    Remains unchanged

    C)                    Increases \[k\] times

    D)                    Increases \[{{k}^{-1}}\] times

    Correct Answer: A

    Solution :

                         \[{F}'=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}=\frac{F}{K}\]                    If F is the force in air, then \[{F}'\] is less than F since \[K>1\]. 


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