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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    \[_{89}A{{c}^{231}}\] gives \[_{82}P{{b}^{207}}\] after emission of some \[\alpha \]and \[\beta \]-particles. The number of such \[\alpha \] and \[\beta \]-particles are respectively               [MP PMT 1993; UPSEAT 2001]

    A)                 5, 6        

    B)                 6, 5

    C)                 7, 5        

    D)                 5, 7

    Correct Answer: B

    Solution :

           Number of a-particles = \[\frac{231-207}{4}=6\]                                 Number of b-particles \[=89-82-2\times 6=5\].


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