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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    The number of \[\alpha \] and \[\beta -\]particles emitted in the nuclear reaction \[_{92}{{U}^{238}}{{\to }_{90}}T{{h}^{234}}{{\to }_{91}}P{{a}^{234}}\]are respectively [Pb.CET 2001]

    A)                 1 and 1 

    B)                 1 and 2

    C)                 2 and 1 

    D)                 2 and 2

    Correct Answer: A

    Solution :

               \[_{92}{{U}^{238}}\xrightarrow{{}}{{\,}_{90}}T{{h}^{234}}\xrightarrow{{}}{{\,}_{91}}P{{a}^{234}}\]                    No. of \[\alpha \] particle \[=\frac{238-234}{4}=\frac{4}{4}=1\]                                 No. of \[\beta \] particle \[=91-90=1\]


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