A) 1, 3
B) 1, 4
C) 1, 2
D) 1, 5
Correct Answer: C
Solution :
\[_{84}{{X}^{218}}\to {{\,}_{84}}{{Y}^{214}}+x{{\,}_{+2}}{{\alpha }^{4}}+y{{\,}_{-1}}{{\beta }^{0}}\] no. of a-particle = \[\frac{218-214}{4}=\frac{4}{4}=1\] no. of b-particle = \[84-84+2\times 1=2\].You need to login to perform this action.
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