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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    The number of \[\alpha -\]and \[\beta -\]particles emitted when a radioactive element \[_{90}{{E}^{232}}\] changes into \[_{86}{{G}^{220}}\] will be   [MP PET 2004]

    A)                 5 and 4

    B)                 2 and 3

    C)                 3 and 2 

    D)                 4 and 1

    Correct Answer: C

    Solution :

               \[_{90}{{E}^{232}}\xrightarrow{{}}{{\,}_{86}}{{G}^{220}}\]                    No. of \[\alpha \] particle =\[\frac{232-220}{4}=3\]                                 No. of \[\beta \] particle \[=86-[90-2\times 3]=2\]


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