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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    The number \[\alpha -\]and \[\beta \]- particles emitted respectively during the transformation of \[_{90}^{232}Th\ \text{to}\ _{82}^{208}Pb\]is [Kerala PMT 2004]

    A)                 3, 6        

    B)                 6, 3

    C)                 4, 6        

    D)                 6, 4

    E)                 6, 8

    Correct Answer: D

    Solution :

               \[_{90}T{{h}^{232}}\,\xrightarrow{{}}{{\,}_{82}}P{{b}^{208}}\]                    No. of \[\alpha \]- particle \[\Rightarrow \frac{232-208}{4}=6\]                                 No. of \[\beta \]- particle \[\Rightarrow \,82-[90-6\times 2]=4\]


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