JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    The nuclear binding energy for \[Ar\](39.962384 amu) is: (given mass of proton and neutron are 1.007825 amu and 1.008665 amu respectively)         [Pb.CET 2002]

    A)                 \[343.81\ MeV\]              

    B)                 \[0.369096\ MeV\]

    C)                 \[931\ MeV\]    

    D)                 None of these

    Correct Answer: A

    Solution :

               \[_{18}A{{r}^{40}}\]                    Total no of protons = 18                    Total no of neutrons = 22                    Mass defect \[=[m\times p+m\times n]-39.962384\]                    \[=[1.007825\times 18+1.008665\times 22]-39.962384\]                    \[=[18.14085+22.19063]-39.962384\] \[=0.369\]                    Binding energy = mass defect \[\times \] 931                                 \[=0.369\times 931=343.62\,MeV\]


You need to login to perform this action.
You will be redirected in 3 sec spinner