A) 7
B) 14
C) 6
D) 8
Correct Answer: D
Solution :
\[_{6}{{X}^{14}}\xrightarrow{\beta }{{\,}_{6+1}}{{N}^{14}}\] in \[_{6}{{X}^{14}}\] no. of neutrons 14 ? 6 = 8.
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