A) \[_{82}P{{b}^{209}}\]
B) \[_{83}B{{i}^{209}}\]
C) \[_{82}P{{b}^{208}}\]
D) \[_{82}P{{b}^{206}}\]
Correct Answer: C
Solution :
Pb ? 208 is the stable end product of thorium series.
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