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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    \[_{92}^{238}U\] emits 8 a-particles and 6 b-particles. The neutron/proton ratio in the product nucleus is  [AIIMS 2005]

    A)                 60/41    

    B)                 61/40

    C)                 62/41    

    D)                 61/42

    Correct Answer: C

    Solution :

           92U238 \[\underset{-6\beta }{\mathop{\xrightarrow{-8\alpha }}}\,\]82X206                    Number of protons = 82; Number of neutrons = 124                                 Neutron/proton ratio in the product nucleus \[=\frac{124}{82}=\frac{62}{41}\]


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