A) 119 neutrons and 119 protons
B) 142 neutrons and 90 protons
C) 144 neutrons and 92 protons
D) 146 neutrons and 90 protons
Correct Answer: B
Solution :
\[_{92}{{U}^{236}}\to {{\,}_{90}}{{X}^{232}}+{{\,}_{2}}H{{e}^{4}}\] \[_{90}{{X}^{232}}\] have 90 protons and 142 neutrons.
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