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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    In the nuclear reaction \[_{92}{{U}^{238}}{{\to }_{82}}P{{b}^{206}}\], the number of alpha and beta particles decayed are [DPMT 1983; MNR 1985; Roorkee Qualifying 1998]

    A)                 \[4\alpha ,\,3\beta \]    

    B)                 \[8\alpha ,\,6\beta \]

    C)                 \[6\alpha ,\,4\beta \]    

    D)                 \[7\alpha ,\,5\beta \]

    Correct Answer: B

    Solution :

           Number of a-particles = \[\frac{238-206}{4}=8\]                                 Number of b-particles = \[92-82-2\times 8=6\].


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