JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    What is the symbol for the nucleus remaining after \[_{20}C{{a}^{42}}\] undergoes \[\beta \]-emission [MNR 1987; UPSEAT 2000, 02]

    A)                 \[_{21}C{{a}^{42}}\]       

    B)                 \[_{20}S{{c}^{42}}\]

    C)                 \[_{21}S{{c}^{42}}\]       

    D)                 \[_{21}S{{c}^{41}}\]

    Correct Answer: C

    Solution :

              \[_{20}C{{a}^{42}}{{\to }_{21}}S{{c}^{42}}{{+}_{-1}}{{e}^{0}}\]


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