JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    On bombarding \[_{8}{{O}^{16}}\] with deutrons, the nuclei of the product formed will be          [NCERT 1978]

    A)                 \[_{9}{{F}^{18}}\]            

    B)                 \[_{9}{{F}^{17}}\]

    C)                 \[_{8}{{O}^{17}}\]

    D)                 \[_{7}{{N}^{14}}\]

    Correct Answer: A

    Solution :

                    \[_{8}{{O}^{16}}+{{\,}_{1}}{{H}^{2}}\to {{\,}_{9}}{{F}^{18}}\]


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