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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    After the emission of one \[\alpha \]-particle followed by one \[\beta -\]particle from the atom of \[_{92}{{X}^{238}}\], the number of neutrons in the atom will be                [CBSE PMT 1995]

    A)                 142        

    B)                 146

    C)                 144        

    D)                 143

    Correct Answer: D

    Solution :

           \[_{92}{{X}^{238}}\xrightarrow{-\alpha }{{\,}_{90}}\,{{Y}^{234}}\xrightarrow{-\beta }{{\,}_{91}}{{Z}^{234}}\]                                 no. of neutrons = 234 ? 91 = 143.


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