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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    After the emission of \[\alpha \]-particle from the atom \[_{92}{{X}^{238}}\], the number of neutrons in the atom will be [MNR 1993; UPSEAT 1999, 2001, 02]

    A)                 138        

    B)                 140

    C)                 144        

    D)                 150

    Correct Answer: C

    Solution :

           \[_{92}{{X}^{238}}{{\xrightarrow{-\alpha }}_{90}}{{Y}^{234}}\]                                 Number of neutrons = \[234-90=144\].


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