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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Causes of radioactivity and Group displacement law

  • question_answer
    The number of \[\alpha \] and \[\beta \]- particles emitted in the nuclear reaction \[_{90}T{{h}^{228}}{{\to }_{83}}B{{i}^{212}}\] are respectively [MNR 1992; MP PMT 1993; AFMC 1998, 2001; MH CET 1999; UPSEAT 2000, 01;  AMU 2001; CPMT 2002]

    A)                 4, 1        

    B)                 3, 7

    C)                 8, 1        

    D)                 4, 7

    Correct Answer: A

    Solution :

           \[_{90}T{{h}^{228}}{{\to }_{83}}B{{i}^{212}}\]                    No. of \[\alpha \]-particles = \[\frac{228-212}{4}=\frac{16}{4}=4\]                                 No. of \[\beta \]-particles = \[90-83-2\times 4=1\].


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