A) \[e>p>\alpha \]
B) \[p>\alpha >e\]
C) \[e>\alpha >p\]
D) None of these
Correct Answer: A
Solution :
\[\because \,\,\,{{m}_{e}}<{{m}_{p}}<{{m}_{\alpha }}\] Þ \[{{\left( \frac{q}{m} \right)}_{e}}>{{\left( \frac{q}{m} \right)}_{p}}>{{\left( \frac{q}{m} \right)}_{\alpha }}\]
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