12th Class Chemistry Solutions / विलयन Question Bank Case Based - Solutions

  • question_answer
    When a gas is bubbled through water at 298 K, a very dilute solution of the gas is obtained. Henry's law constant for the gas at 298 K is 150 kbar. If the gas exerts a partial pressure of 2 bar, the number of millimoles of the gas dissolved in 1 L of water is

    A) 0.55

    B) 0.87

    C) 0.37

    D) 0.66

    Correct Answer: C

    Solution :

    The mole fraction of the gas in solution \[x=\frac{p}{{{K}_{H}}}=\frac{1}{150\times {{10}^{3}}}\] If n is the number of moles of gas in a solution of 1 L of water containing 55.5 mol then \[x=\frac{n}{n+55.5}\]or, \[\frac{n}{55.5}\]=\[\frac{1}{150\times {{10}^{3}}}\] [n + 5.55 \[\approx \] 55.5, as n is very small] \[n=\frac{55.5}{150}\times {{10}^{-3}}=0.37\]millimoles


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