A) (7, 24, 25)
B) (15, 8, 17)
C) (5, 12, 13)
D) (21, 20, 28)
Correct Answer: D
Solution :
[a] Now, \[{{24}^{2}}+{{7}^{2}}=576+49\] \[=\text{ }625\text{ }=\text{ }{{25}^{2}}\], which forms a Pythagoras triplet [b] \[{{15}^{2}}+{{8}^{2}}=225+64=289={{17}^{2}}\], which forms a Pythagoras triplet [c] \[{{12}^{2}}+{{5}^{2}}=144+25=169={{13}^{2}}\], which form a Pythagoras triplet. [d] \[{{20}^{2}}+{{21}^{2}}=400+441=881\ne {{28}^{2}}\], which does not form a Pythagoras triplet.
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