A) 50m
B) 12m
C) 100m
D) 70m
Correct Answer: A
Solution :
In right \[\Delta ADC\], use Pythagoras theorem, \[AC=\sqrt{A{{D}^{2}}+C{{D}^{2}}}\] \[=\sqrt{{{\left( 30 \right)}^{2}}+{{\left( 40 \right)}^{2}}}\] \[=\sqrt{900+1600}=\sqrt{2500}=50\,m\]
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