10th Class Mathematics Triangles Question Bank Case Based MCQs - Triangles

  • question_answer
    Length of AE =

    A) \[\frac{2}{3}\times BE\]

    B) \[\sqrt{A{{D}^{2}}-D{{E}^{2}}}\]

    C) \[\frac{4}{3}\times \sqrt{B{{C}^{2}}-C{{E}^{2}}}\]

    D) AII of these

    Correct Answer: C

    Solution :

    \[\frac{AE}{BE}=\frac{4}{3}\] \[AE=\frac{4}{3}\times BE=\frac{4}{3}\times 3=4\,cm\] \[\frac{4}{3}\sqrt{B{{C}^{2}}-C{{E}^{2}}}=\frac{4}{3}\sqrt{25-16}\] \[=\frac{4}{3}\times 3=4\,\,\,cm\]


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